# Pre release Material 2018

**Update: Oct/Nov 2018 Pre release Material uploaded, click here**

In preparation for the examination candidates should attempt the following practical tasks by writing and testing a program or programs.

A farmer records the milk production of a herd of cows. Every cow has a unique 3-digit identity code.

Each cow can be milked twice a day, seven days a week. The volume of the milk from each cow is recorded in liters correct to one decimal place (yield) every time the cow is milked. The size of the herd is fixed. At the end of the week the total and the average yield for each cow for the week is calculated.

The farmer identifies the cow that has produced the most milk that week. The farmer also identifies any cows that have produced less than 12 liters of milk on four or more days that week.

A program is required to record the yield for each cow every time it is milked, calculate the total weekly volume of milk for the herd and the average yield per cow in a week. The program must also identify the cow with the best yield that week and identify any cow with a yield of less than 12 liters of milk for four or more days that week.

Write and test a program or programs for the farmer.Your program of programs must include the appropriate prompts for the entry of data.

- Error messages and other output need to be set out clearly and understandably.
- All variables, constants and other identifiers must have meaningful names
- You will need to complete these three tasks. Each task must be fully tested.

**TASK 1 – Record the yield**

Write a program for TASK 1 to record the milk yields for a week. The program records and stores theidentify code number and the yield every time a cow is milked.

**TASK 2 – Calculate the statistics**

Using your recorded data from TASK 1, calculate and display the total weekly volume of milk for the herd to nearest while liter. Calculate and display the average yield per cow in a week to the nearest whole liter.ico calendar

**TASK 3 – Identify the most productive and cows that are producing a low volume of milk.**

Extend TASK 2 to identify and display the identity code number and weekly yield of the cow that has produced the most milk. Also identify and display the identity code numbers of any cows with a yield of less than 12 liters of milk for four days or more in the week.

## Visual Basic (Forms base) Solution

**Task1 **

[vb]

Dim nofcows, cowid As Integer

Dim morning, evening, weektotalcow As Single

nofcows = InputBox("How many cows in a herd ? ")

Dim cowids(0 To nofcows) As Integer

Dim milkstore(0 To nofcows) As Single

For cows = 1 To nofcows

cowid = InputBox(" Enter cow ID ")

While cowid < 100 Or cowid > 999

MsgBox(" You have entred the wrong ID. Enter 3 number code. ")

cowid = InputBox(" Enter cow ID ")

End While

cowids(cows) = cowid

Next

For cows = 1 To nofcows

MsgBox(" Enter Milk Yield for cow ID no : " & cowids(cows))

For days = 1 To 7

MsgBox(" For day : " & days)

morning = InputBox(" Morning Yield in liters for cow ")

evening = InputBox(" Evening Yield in liters for cow ")

weektotalcow = weektotalcow + morning + evening

Next

milkstore(cows) = weektotalcow

Next

[/vb]

**Task 2**

[vb]

Dim total_yield, avg_yield As Single

For cows = 1 To nofcows

avg_yield = milkstore(cows) / nofcows

MsgBox(" The average Yield of cow ID no " & cowids(cows) & " is : " &

Math.Round(avg_yield))

total_yield = total_yield + milkstore(cows)

Next

MsgBox(" The total weekly volume of milk for the herd : " &

Math.Round(total_yield))

[/vb]

**Task 3**

[vb]

Dim highest_yeild As Single

Dim highest_ID As Integer

highest_yeild = 0

For cows = 1 To nofcows

If milkstore(cows) > highest_yeild Then

highest_yeild = milkstore(cows)

highest_ID = cowids(cows)

End IfPre Release Material CS 2210 O Levels Summers 2018

A Project Of csmeasy.com

Next

MsgBox(" The Cow ID no : " & highest_ID & " has produced the highest yeild " &

highest_yeild)

For cows = 1 To nofcows

If milkstore(cows) < 12.0 Then

MsgBox(" The cow ID no " & cowids(cows) & " has produced less then 12

Liters In a week")

End If

Next

End Sub

End Class

[/vb]

**Credits to : Engr. Bandeshah for the Visual Basic Solution**

## Python Solution

**Task 1**

[py]

#Recording the yield

Cow = []

Yield = []

Cows = int(input("How many cows are in the herd? "))

Day = 0 #to configure the milking

for i in range(14):

if i%2 == 1:

Milking = "Second"

else:

Milking = "First"

Day += 1

print("Day ", Day, "; ", Milking, " milking")

for i in range(Cows):

while True:

Code = int(input("Enter code: "))

if Code > 999 or Code < 100:

print("Enter a 3-digit code please")

else:

Cow.append(Code)

break

Y = float(input("Enter volume of milk in litres: ")) #A range check for yield can be added

Yield.append(Y)

[/py]

**Task 2**

[py]

#Finding the Total and Average

Total = 0

for i in range(len(Yield)):

Total += Yield[i]

Average = Total/Cows

round(Total, 0)

round(Average, 0)

print("Total weekly volume of milk: ", int(Total), " litres")

print("Average yield per cow: ", int(Average), " litres")

[/py]

**Task 3**

[py]

#Identifying most productive and low producing cows

Total = []

LessMilk = ""

YieldOnDay = 0

Milking = 0

for j in range(Cows):

T = 0

Days = 0

Cow = Cow[j] #A cow chosen

for i in range(len(Cow)):

if Cow[i] == Cow:

T += Yield[i] #Incrementing the total for each cow

YieldOnDay += Yield[i]

Milking += 1

if Milking == 2: # 2 since checking for days, not milkings

if YieldOnDay < 12: #Checking if yield is less than 12 Days += 1 Milking = 0 YieldOnDay = 0 if Days > 3: #Low yield for 4 or more days

LessMilk = LessMilk + str(Cow[j]) + ", "

Total.append(T)

print(Total)

for i in range(Cows):

if Total[i] == max(Total):

print("Cow ", Cow[i], " has the highest yield of ", Total[i], " litres")

print("Cows which produced less than 12 litres of milk: " , LessMilk)

[/py]

**Update: Oct/Nov 2018 Pre release Material uploaded, click here**

Pingback: O level Computer science Pre release material Oct/Nov 2017 Solution

Can i get the answer in psedocode please…

Doesn’t solve the unique ID problem

Can i get the answer in psedocode please…

For pre-release material in PESEDUCODE contact me at shayanriazahmed123@gmail.com or 03332622989

The task 3 specifically states “identify and display the identity code numbers of any cows with a yield of less than 12 liters of milk **for four days or more** in the week”. Your variable “milkstore” stores the total weekly volume of milk yield from each cow so how can this requirement of the task be satisfied by this statement of your program: “If milkstore(cows) < 12.0 ….."

????

avg_yield = milkstore(cows) / nofcows

This statement seems to me incorrect. Here we are dividing 1 cow yield by noofcows which seems incorrect. It should be either noofdays(7) or we have complete total of milk yield for all the cows. These are my suggestions.

It says the size of the herd if fixed, still your asking to input the size of the herd (I think this is a constant candidate). Furthermore, the three digit check is wrong, what if the three digit is 000 or 099?

three digit starts from 100

in computer 0s are count as ‘off’ , three digit ; would mean that 1000

Anyone needs Visual Basic Console Application Solution for IGCSE / O- levels Pre Release material June 2018

Contact me at my email

alidoqman1@gmail.com

I TOO NEEDED THE SOLUTION IN PSEUDO CODES

Good Job but one point is not considered here which is very important for marks. “for 4 or more days”

there should be counter for those days.

Are there answers for IGCSE?

Oct/nov 2018 Pre release : http://gcecompilation.com/o-level-computer-science-pre-release-material-2018-oct-nov-solution/